-0.04x^2+3x+1=0

Solution for -0.04x^2+3x+1=0 equation:

-0.04x^2+3x+1=0

a = -0.04; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·(-0.04)·1
Δ = 9.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{9.16}}{2*-0.04}=\frac{-3-\sqrt{9.16}}{-0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{9.16}}{2*-0.04}=\frac{-3+\sqrt{9.16}}{-0.08}
$